- #1

- 53

- 0

So far I have cos theta = (1-t^2)/(1+t^2). After squaring this and doing various substitutions, I get (cos theta)^3, which can't be right.

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- Thread starter redshift
- Start date

- #1

- 53

- 0

So far I have cos theta = (1-t^2)/(1+t^2). After squaring this and doing various substitutions, I get (cos theta)^3, which can't be right.

- #2

Tide

Science Advisor

Homework Helper

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[tex]\cos^3 \theta = \cos^2 \theta \cos \theta = \left(1-\sin^2 \theta \right) \frac {d \sin \theta}{d\theta}[/tex]

- #3

- 53

- 0

Many thanks. I'll give it a shot.

- #4

- 53

- 0

I got cos theta - (1/3)cos^3 theta + C

Does this look right?

Does this look right?

- #5

Fredrik

Staff Emeritus

Science Advisor

Gold Member

- 10,872

- 418

Almost. It should be sin, not cos.

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