Abstract

Recovery of the full 2f wavelength modulation spectroscopy (WMS) signal in isolation from the 2f residual amplitude modulation (RAM) due to nonlinear intensity modulation (IM) and distortion due to linear IM is demonstrated. The 2f RAM is eliminated using a fiber delay line, while the linear IM-induced distortion is eliminated by a phasor decomposition approach. This generic and robust two-pronged strategy removes the need to separately measure the 2f RAM in high-modulation-index calibration-free 2f WMS. It is also important for widely tunable 2f WMS using nontelecom diode lasers with highly nonlinear characteristics leading to high-2f RAM levels.

© 2010 Optical Society of America

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References

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2004

J. T. C. Liu, J. B. Jeffries, and R. K. Hanson, Appl. Phys. B 78, 503 (2004).
[CrossRef]

J. T. C. Liu, J. B. Jeffries, and R. K. Hanson, Appl. Opt. 43, 6500 (2004).
[CrossRef] [PubMed]

Amann, M.

Chakraborty, A. L.

Chen, J.

Duffin, K.

Hangauer, A.

Hanson, R. K.

Jeffries, J. B.

Johnstone, W.

Lengden, M.

Li, H.

Liu, J. T. C.

J. T. C. Liu, J. B. Jeffries, and R. K. Hanson, Appl. Opt. 43, 6500 (2004).
[CrossRef] [PubMed]

J. T. C. Liu, J. B. Jeffries, and R. K. Hanson, Appl. Phys. B 78, 503 (2004).
[CrossRef]

Liu, X.

McGettrick, A. J.

Moodie, D. G.

Ortsiefer, M.

Reiker, G. B.

Rieker, G. B.

Ruxton, K.

Stewart, G.

Strzoda, R.

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Figures (4)

Fig. 1
Fig. 1

RAM-nulling experimental setup. Gas cell comprises graded-index (GRIN) lenses with a 9.9 cm path length in between. SMF-28 is used as delay a fiber.

Fig. 2
Fig. 2

Non-nulled 2 f signals for increasing m values for 1.02% CH 4 at 0.552 bar and 17.4 ° C , 9.9 cm path length and peak absorbance of 0.0275.

Fig. 3
Fig. 3

Background RAM-nulled 2 f signals for the same experimental configurations as in Fig. 2.

Fig. 4
Fig. 4

PD of 2 f signals for 1.02% CH 4 at 1.002 bar and 20.3 ° C , 9.9 cm path length and peak absorbance of 0.0275 for m = 2.2 and m = 2.9 .

Equations (3)

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I 2 ω Ch X = 0.25 I ( λ ) · α ( λ ) · C · l · ( δ λ ) 2 0.5 Δ I 1 ( λ ) · α ( λ ) · C · l · δ λ · cos ψ .
I 2 ω Ch Y = 0.5 Δ I 1 ( λ ) · α ( λ ) · C · l · δ λ · sin ψ ,
I 2 ω = I 2 ω Ch X I 2 ω Ch Y / tan ψ .

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