Abstract

We present a three-dimensional imaging method using a pulsed laser as a flood illuminating source and an intensified camera as the receiver with exponentially modulated gain. The depth map of a scene is obtained from two intensity images and the depth accuracy is independent of the depth of the target in the scene. We demonstrate a depth-independent depth accuracy of 0.32 m in an indoor experiment and obtain a depth map of an outdoor scene ranging from 150 to 180 m under a lower signal to noise ratio condition.

© 2009 Optical Society of America

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References

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  1. J. Busck and H. Heiselberg, Proc. SPIE 5412, 257 (2004).
    [CrossRef]
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    [CrossRef] [PubMed]
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2009 (1)

2008 (1)

2007 (1)

2006 (2)

2005 (1)

J. Busck, Opt. Eng. 44, 116001 (2005).
[CrossRef]

2004 (2)

J. Busck and H. Heiselberg, Proc. SPIE 5412, 257 (2004).
[CrossRef]

J. Busck and H. Heiselberg, Appl. Opt. 43, 4705 (2004).
[CrossRef] [PubMed]

1980 (1)

1979 (1)

Andersen, J. F.

Andersson, P.

P. Andersson, Opt. Eng. 45, 034301 (2006).
[CrossRef]

Busck, J.

Christnacher, F.

Csorba, I. P.

Eberhardt, E. H.

Heiselberg, H.

Huimin, Y.

Jin, C.

Laurenzis, M.

Liu, L.

Monnin, D.

Sun, X.

Xiuda, Z.

Yanbing, J.

Zhang, Y.

Zhao, Y.

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Figures (5)

Fig. 1
Fig. 1

Time sequence of emitted light pulse, received light pulse, receiver gate, and receiver gain.

Fig. 2
Fig. 2

Results of indoor experiment: (a) targets in indoor experiment, (b) intensity image with constant gain, (c) intensity image with exponentially modulated gain, (d) intensity image with linearly modulated gain.

Fig. 3
Fig. 3

Depth map in indoor experiment: (a) depth map with exponentially modulated gain, (b) depth map with linearly modulated gain.

Fig. 4
Fig. 4

Measured results of depth in indoor experiment: (a) measured depth under exponentially modulated gain, (b) measured depth under linearly modulated gain.

Fig. 5
Fig. 5

Results of outdoor experiment: (a) photograph of outdoor buildings, (b) intensity image with constant gain, (c) depth map.

Equations (9)

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E m = γ   exp ( α z ) S z 2 P ( t 2 z c ) g m ( t 2 z 0 c ) d t
= γ   exp ( α z ) S z 2 P ( t ) g m ( t + 2 z c 2 z 0 c ) d t ,
g m ( t ) = g 0   exp ( t / τ e ) ,
E m = g 0   exp [ 2 ( z z 0 ) c τ e ] γ   exp ( α z ) S z 2 P ( t ) exp ( t τ e ) d t .
E c = γ   exp ( α z ) S z 2 g c P ( t ) d t .
z = z 0 + c τ e 2 ln ( E m β E c ) ,
β = g 0 P ( t ) exp ( t τ e ) d t g c P ( t ) d t .
σ z 2 = ( c τ e 2 ) 2 ( σ E c 2 E c 2 + σ E m 2 E m 2 ) + ( c 2 ) 2 σ t r 2 ,
σ z 2 c τ e 2 SNR out ,

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