Abstract

An integral imaging method based on microscanning of a microlens array is proposed. The effects of micro scanning on the depth resolution and the product of depth of focus and lateral resolution squared (PDLRS) of an integral imaging system are quantitatively analyzed. Calculation results show that microscanning can improve not only the depth resolution, but the PDLRS can be increased. The amount of improvement of different microscanning modes to the performance of integral imaging is closely related to the fill factor of the detector and the diffraction factor of the microlens.

© 2008 Optical Society of America

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References

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    [CrossRef]
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    [CrossRef] [PubMed]
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    [CrossRef] [PubMed]

2007 (1)

2005 (1)

2004 (1)

2003 (1)

J.-S. Jang and B. Javidi, Proc. SPIE 5202, 12 (2003).
[CrossRef]

2002 (1)

J.-S. Jang and B. Javidi, Proc. SPIE 4864, 60 (2002).
[CrossRef]

1999 (1)

O. Hadar and G. D. Boreman, Opt. Eng. 38, 782 (1999).
[CrossRef]

1996 (1)

J. Fortin and P. Chevrette, Proc. SPIE 2743, 185 (1996).
[CrossRef]

Opt. Eng. (1)

O. Hadar and G. D. Boreman, Opt. Eng. 38, 782 (1999).
[CrossRef]

Opt. Lett. (3)

Proc. SPIE (3)

J.-S. Jang and B. Javidi, Proc. SPIE 5202, 12 (2003).
[CrossRef]

J.-S. Jang and B. Javidi, Proc. SPIE 4864, 60 (2002).
[CrossRef]

J. Fortin and P. Chevrette, Proc. SPIE 2743, 185 (1996).
[CrossRef]

Other (1)

G. C. Holst, Electro-Optical Imaging System Performance, 3rd ed. (SPIE, 2003), p. 90.

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Figures (3)

Fig. 1
Fig. 1

Schematic of InI system based on MS of the microlens array.

Fig. 2
Fig. 2

Relative amount of improvement in the depth resolution of InI versus the sampling number of MS (for different fill factors).

Fig. 3
Fig. 3

Relationship of PDLRS with sampling number (for different fill factors).

Equations (8)

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MTF total = MTF optics ( ξ ) PTF MS ( ξ ) .
MTF total = 2 π { arccos ( ξ ξ c ) ξ ξ c [ 1 ( ξ ξ c ) 2 ] 1 2 } sin ( π Δ ξ ) π Δ ξ sin ( π a ξ ) π a ξ ,
Δ = p n , a = η 1 p , ξ c = 1 s = 1 ( η 2 p ) ,
π 3 40 η 1 t 2 n = { arccos ( η 2 t ) η 2 t [ 1 ( η 2 t ) 2 ] 1 2 } sin ( π η 1 t ) sin ( π t n ) .
N = d ξ max = d t p ,
R d = 0.3 d t p g ,
β = R d MS R d non - MS R d non - MS = 0.3 d t MS 0.3 d t non - MS p g 0.3 d t non - MS p g = t MS t non - MS t non - MS .
PDLRS = 1 λ ( 2 λ d t g 2 λ d t g + p d 2 ) 2 ,

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