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## Homework Statement

I'm searching for the integral that gives arcosu

## Homework Equations

as we know : ∫u'/[1-u^2]^0.5 dx = arcsinu

derivative of arccosu = -u'/[1-u^2]^0.5 + C

derivative of arcsinu= u'/[1-u^2]^0.5

## The Attempt at a Solution

when I type the -u'/[1-u^2]^0.5 on the online integral calculator it always gives me -arcsinu +C

Why it doesn't gives arccosu

is the arccosu=-arcsinu?!

and what is the integral that gives arcosu?