## Abstract

When two entangled qubits, each owned by Alice and Bob, undergo separate decoherence, the amount of entanglement is reduced, and often, weak decoherence causes complete loss of entanglement, known as entanglement sudden death. Here we show that it is possible to apply quantum measurement reversal on a single-qubit to avoid entanglement sudden death, rather than on both qubits. Our scheme has important applications in quantum information processing protocols based on distributed or stored entangled qubits as they are subject to decoherence.

© 2014 Optical Society of America

## 1. Introduction

Quantum entanglement is an essential resource for quantum information processing including quantum computation [1, 2] and quantum communication [3–5]. However, decoherence due to irreversible interactions with the environment causes degradation of entanglement, and, in some cases, leads to entanglement sudden death (ESD) in which entanglement is completely lost before its subsystem is fully decohered [6, 7]. Since overcoming decoherence is required for practical realization of quantum information protocols, various schemes for suppressing decoherence have been reported [8–15].

Recently, it has been shown that quantum measurement reversal, a set of weak and reversing measurements [16–20], can effectively suppress decoherence [21–24]. Without quantum measurement reversal, decoherence causes the qubit to end-up in a mixed state due to the loss of quantum coherence, while if quantum measurement reversal is introduced as shown in Fig. 1(a), the initial state may be preserved even in the presence of decoherence [21,22]. This decoherence suppression scheme can also be applied to multi-qubit systems, in particular, it has been shown that entanglement of two-qubit states that undergo separate decoherence can be protected by using two sets of single-qubit quantum measurement reversal steps, see Fig. 1(b) [24]. In some cases, decoherence affecting on both subsystems of two-qubit entangled states causes complete loss of entanglement, i.e., ESD [6]. Interestingly, even in this severe circumstance, the initial entanglement can be protected by performing quantum measurement reversal on both qubits. Avoiding ESD is essential in entanglement distribution between two distant parties, since once distributed entangled qubits completely lose entanglement, entanglement cannot be distilled between them [25–28].

A question then naturally arises whether preventing an entangled state from completely losing entanglement against ESD is possible by quantum measurement reversal performed only on one of the qubits rather than on both qubits as shown in Fig. 1(c). For instance, between Alice and Bob who initially share two entangled qubits, only Alice performs quantum measurement reversal on her qubit. In this work, we demonstrate that Alice alone can avoid ESD by performing quantum measurement reversal only on her qubit.

## 2. Theory

Consider the situation in which a two-qubit entangled state is affected by separate decoherence. Initially, Alice and Bob share two-qubit pure entangled state |Φ〉 = *α*|00〉+β|11〉 where |*α*|^{2} + |*β*|^{2} = 1 as shown in Fig. 2(a). We assume that each qubit independently suffers from amplitude damping decoherence. In general, amplitude damping decoherence arises due to the interaction between the system (S) and the environment (E) and amplitude damping for a single qubit can be represented by the following operation, |0〉* _{S}*|0〉

*→ |0〉*

_{E}*|0〉*

_{S}*and ${|1\u3009}_{S}{|0\u3009}_{E}\to \sqrt{D}{|1\u3009}_{S}{|0\u3009}_{E}+\sqrt{D}{|0\u3009}_{S}{|1\u3009}_{E}$, where 0 ≤*

_{E}*D*≤ 1 is the magnitude of the decoherence and

*D̄*≡ 1−

*D*. Amplitude damping usually describes the energy dissipation process, for instance, it can be observed from the state of an atom which spontaneously decays, the state of a photon in an leaky cavity or an interferometer, and the zero-temperature energy relaxation of a superconducting qubit [19, 29].

Although Alice and Bob initially share a pure entangled state |Φ〉, the resulting state *ρ _{D}* is not a pure state since each particle suffers from amplitude damping decoherence with strengths of

*D*and

_{A}*D*, respectively [7, 24]. The concurrence [30] of the final state

_{B}*ρ*,

_{D}*C*is given by

_{D}*C*= Λ

_{D}*if Λ*

_{D}*> 0 and*

_{D}*C*is always less than the concurrence of the initial state, 2 |

_{D}*αβ*|. From Eq. (1), it is clear that for |

*α*| ≥ |

*β*|,

*C*= 0 only when

_{D}*D*= 1 or

_{A}*D*= 1, meaning that the entanglement exists except the case that the final state

_{B}*ρ*is fully damped by decoherence (

_{D}*D*= 1). On the other hand, for |

_{i}*α*| < |

*β*|, entanglement completely disappears when $\sqrt{{D}_{A}{D}_{B}}>|\alpha /\beta |$, which is clearly less than the maximum level of the decoherence. Thus, ESD occurs only if |

*α*| < |

*β*| [7].

Let us now describe our strategy to avoid ESD as shown in Fig. 2(b). At first, Alice and Bob initially share a pure entangled state |Φ〉. Then, Alice performs a weak measurement *W _{A}*(

*p*) on her qubit before her qubit undergoes decoherence, see Fig. 2(b). Here, weak measurement partially collapses a single qubit state towards |0〉

*. The weak measurement operator*

_{S}*W*(

*p*) can be written as $W(p)=|0\u3009\u30080|+\sqrt{1-p}|1\u3009\u30081|$ where

*p*is the strength of the weak measurement [20]. Since only |1〉

*state undergoes decoherence, the system states can partially avoid decoherence by reducing the portion of |1〉*

_{S}*state with weak measurements. Note that the initial state |Φ〉 is transformed into |Φ′〉 by a weak measurement and |Φ′〉 is still a pure state.*

_{S}Then each qubit undergoes separate decoherence and |Φ′〉 evolves to a mixed state ρ′. Alice now performs a reversing measurement *R _{A}* (

*p*) on her qubit as shown in Fig. 2(b). A reversing measurement is also a weak measurement but it partially collapses the state towards the opposite direction, i.e., |1〉

_{r}*. The reversing measurement operator is given as $R({p}_{r})=\sqrt{1-{p}_{r}}|0\u3009\u30080|+|1\u3009\u30081|$ where*

_{S}*p*is the strength of the reversing measurement. The reversing strength we used is

_{r}*p*=

_{r}*p*+

*D*where

_{A}p̄*p̄*≡ 1 −

*p*[21]. Here, Bob does not play any role in the whole procedure. Note that the scheme also works well if only Bob carries out single-qubit quantum measurement reversal on his qubit, i.e.,

*W*(

_{B}*p*) and

*R*(

_{B}*p*). Note that the strength of the reversing measurement which Bob performs on his qubit is

_{r}*p*=

_{r}*p*+

*D*.

_{B}p̄After Alice alone performs the single-qubit quantum measurement reversal on her qubit, the concurrence of the two-qubit state *ρ _{A}*,

*C*, can be evaluated by

_{A}*C*= Λ

_{A}*if Λ*

_{A}*> 0, otherwise*

_{A}*C*= 0. Note that

_{A}*C*>

_{A}*C*, meaning that

_{D}*ρ*is more entangled than

_{A}*ρ*. For the case with Bob’s single-qubit quantum measurement reversal,

_{D}*C*is the same as

_{B}*C*except the fact that

_{A}*D*and

_{A}*D*are interchanged, and

_{B}*C*and

_{A}*C*give the same value when

_{B}*D*=

_{A}*D*=

_{B}*D*.

From Eq. (2), we can find several remarkable results. First of all, Λ* _{A}* is monotonic increasing function of

*p*, meaning that the resulting state

*ρ*becomes more entangled as the weak and reversing strengths increase. Note that the concurrence of the initial state |Φ〉, 2 |

_{A}*αβ*|, cannot be fully retrieved since only Alice performs single-qubit quantum measurement reversal on her qubit. However, even in the ESD condition,

*ρ*can have non-zero entanglement if the strengths of the weak and its corresponding reversing measurements (

_{A}*p*=

_{r}*p*+

*D*) are larger than the threshold value, i.e.,

_{A}p̄*p*≥ 1 − |

*α/β*|

^{2}/(

*D*). Hence, we can conclude that Alice can avoid ESD by performing single-qubit quantum measurement reversal only on her qubit without Bob’s help. Once Alice and Bob share non-zero entanglement against decoherence, they can prepare a maximally entangled state from multiple copies of less entangled states using entanglement distillation protocols [25–28].

_{A}D_{B}## 3. Experiment

The experimental setup for demonstrating that Alice or Bob alone can avoid ESD and prevent complete loss of entanglement against decoherence using single-qubit quantum measurement reversal is shown in Fig. 3. Two-qubit entangled states are prepared by two-photon polarization states which are generated via spontaneous parametric down conversion process. A 6 mm type-I *β*-BaB_{2}O_{4} crystal is pumped by a 405 nm diode laser beam (100 mW) and a pair of down-converted photons centered at 810 nm are generated on the frequency-degenerate, noncollinear phase matching condition. Each down-converted photon is frequency-filtered using an interference filter with full width at half-maximum bandwidth of 5 nm. Then, the two-qubit entangled state |Φ〉 = *α*|00〉 + *β*|11〉 can be prepared using quantum interferometry [31] and glass-plates oriented at Brewster angle (BPs) [20]. Here, |0〉 and |1〉 correspond to the horizontally (|*H*〉) and vertically (|*V* 〉) polarized photons, respectively.

The weak measurement on the polarization qubit can be implemented using BPs since BP transmits horizontally polarized photons without any reflection while reflecting vertically polarized photons with some probability [20]. The reversing measurement partially collapses the state to the opposite direction, so it can be realized by adding 45° half-wave plates (HWPs) for bit-flip operations before and after BPs. The strengths of weak and reversing measurement *p* and *p _{r}* can be increased by adding more BPs. The amplitude damping decoherence for the photonic system can be realized using a displaced Sagnac interferometer [7,22,24]. In experiment, the system qubit is encoded in the polarization of the single photon (|

*H*〉 = |0〉

*, |*

_{S}*V*〉 = |1〉

*) and the environment qubit is encoded in the path of the single photon, |0〉*

_{S}*and |1〉*

_{E}*, see Fig. 3. Finally, the resulting states are analyzed by quantum state tomography.*

_{E}## 4. Results and analysis

Before confirming whether our scheme works well, we have investigated how the initial entangled state |Φ〉 = *α*|00〉 + *β*|11〉 is affected by the identical decoherence (*D _{A}* =

*D*=

_{B}*D*). We evaluated the concurrence of the final state

*ρ*from the density matrices which are experimentally reconstructed by the quantum state tomography. For the two entangled input states with |

_{D}*α*| = |

*β*| and |

*α*| = 0.481 < |

*β*|, we measured

*C*(Λ

_{D}*) as increasing the strength of the decoherence*

_{D}*D*and the results are shown in Fig. 4(a). As expected,

*C*decreases as

_{D}*D*increases in both cases. Note that ESD is observed for the case of |

*α*| = 0.481.

Then, consider the case that only Alice or Bob alone carries out single-qubit quantum measurement reversal to avoid complete loss of entanglement when each qubit undergoes separate decoherence. We performed the experiment for the identical damping case, i.e., *D _{A}* =

*D*=

_{B}*D*. In addition, to simulate the situation in which ESD can take place, we chose

*D*= 0.617 ± 0.017. Figure 4(b) shows the experimental results for

*C*and

_{A}*C*(Λ

_{B}*and Λ*

_{A}*) as a function of*

_{B}*p*for two initial entangled states. We have collected experimental data up to

*p*= 0.617 due to low success probabilities associated with weak and reversing measurements for larger

*p*. As expected from Eq. (2),

*C*and

_{A}*C*become larger as

_{B}*p*increases. In addition, for the input state with |

*α*| = 0.481 which experiences ESD without introducing quantum measurement reversal,

*C*and

_{A}*C*can have non-zero values when strengths of the weak and reversing measurements are larger than the threshold value. This result demonstrates that Alice and Bob can share non-zero entanglement even in the ESD condition using only single-qubit quantum measurement reversal, i.e., ESD can be avoided by Alice or Bob alone.

_{B}## 5. Conclusion

When two entangled qubits, each owned by Alice and Bob, experience separate decoherence, the amount of entanglement decreases and sometimes ESD occurs. We have demonstrated that Alice or Bob alone overcomes ESD and still share non-zero entanglement after decoherence with quantum measurement reversal on only one of the two entangled qubits. Since any small amount of entanglement shared by Alice and Bob can be concentrated, we believe that our scheme has important applications in quantum information protocols based on distributed or stored entangled qubits as they are subject to decoherence. Moreover, our scheme can be directly applied to other qubit systems experiencing decoherence, such as, two-level atoms with spontaneous decay, superconducting qubits with zero-temperature energy relaxation, and so on.

## Appendix : Reversing measurement strength under decoherence

When an initial quantum state |*ψ*_{in}〉 = *α*|0〉 + *β*|1〉 does not suffer any decoherence (*D* = 0), the reversing measurement for the weak measurement
$W(p)=|0\u3009\u30080|+\sqrt{1-p}|1\u3009\u30081|$ is
$R({p}_{r})=\sqrt{1-{p}_{r}}|0\u3009\u30080|+|1\u3009\u30081|$ with *p _{r}* =

*p*[17]. The quantum state |

*ψ*

_{in}〉 =

*α*|0〉 +

*β*|1〉 is retrieved without errors only when

*p*=

_{r}*p*, and, thus,

*p*=

_{r}*p*is the optimal reversing measurement strength for

*D*= 0. Note that the optimal

*p*is independent on

_{r}*α*in this case.

However, when decoherence is introduced, *p _{r}* =

*p*is not the optimal measurement anymore and the “optimality” of the reversing measurement strength becomes highly non-trivial. In general,

*p*is dependent on several parameters such as

_{r}*D*,

*p*, and

*α*. Since the initial state cannot be retrieved perfectly, the optimal

*p*value is different for maximizing, e.g., the state fidelity, the success probability, the concurrence, etc. Moreover, the optimal

_{r}*p*value is also dependent on the condition of the decoherence suppression scenarios. In this section, we investigate several reversing measurement strategies and compare them with respect to the state fidelity and the success probability. Here, we consider three different situations i) a single qubit state suffers decoherence [21, 22], ii) both subsystems of the two-qubit entangled state suffer from decoherence (the scenarios considered in [24] and in this manuscript), and iii) one subsystem of the two-qubit entangled state suffers from decoherence.

_{r}## A1. Single qubit case

As shown in Fig. 1(a), if a set of weak measurement *W* (*p*) and reversing measurement *R*(*p _{r}*) measurements are performed before and after decoherence (

*D*), an initial qubit state |

*ψ*

_{in}〉 =

*α*|0〉 +

*β*|1〉, where |

*α*|

^{2}+ |

*β*|

^{2}= 1, is transformed to the final state

*ρ*

_{out}, given as

*D̄*≡ 1 −

*D*,

*p̄*≡ 1 −

*p*,

*p̄*≡ 1 −

_{r}*p*. The success probability or channel transmittance is

_{r}*P*=

_{S}*p̄*(|

_{r}*α*|

^{2}+

*Dp̄*|

*β*|

^{2})+

*D̄p̄*|

*β*|

^{2}[21, 22].

One way to quantify performance of the decoherence suppression scheme is evaluating the state fidelity between the initial state *ρ*_{in} = |*ψ*_{in}〉 〈*ψ*_{in}| and the final state *ρ*_{out}, i.e., *F* = 〈*ψ*_{in}|*ρ*_{out} |*ψ*_{in}〉, which is calculated to be

*F*

_{max}is

*α*,

*D*, and

*p*.

However, in practical decoherence scenario, we may assume that we know the magnitude of decoherence *D* while we do not have any prior information about the initial state |*ψ*_{in}〉, i.e., *α* is an unknown parameter [22,24]. We consider two different state independent *p _{r}* values. First, we obtain

*p*by substituting $|\alpha |=1/\sqrt{2}$ into Eq. (5),

_{r}*α*.

Second, we choose *p _{r}* to be
${p}_{r}^{\text{exp}}=p+(1-p)D$ which is used in our paper [21, 22]. The reasons we chose
${p}_{r}^{\text{exp}}$ are the following: i)
${p}_{r}^{\text{exp}}$ is state independent, i.e.,
${p}_{r}^{\text{exp}}$ is not a function of

*α*and ii) the state fidelity

*F*asymptotically approaches to 1 as the weak measurement strength

*p*→ 1 regardless of

*α*.

We now compare the state fidelity values *F* between the initial and final states for two different reversing measurement strength
${p}_{r}^{\text{fix}}$ and
${p}_{r}^{\text{exp}}$. The state fidelity values for the strength of the reversing measurement
${p}_{r}^{\text{fix}}$ and
${p}_{r}^{\text{exp}}$, respectively, are calculated to be

*F*

^{max}can be obtained by substituting ${p}_{r}^{\text{max}}$ to Eq. (3). Note that

*F*

^{max}is always higher than both of

*F*

^{fix}and

*F*

^{exp}regardless of |

*α*|,

*D*, and

*p*. However, to achieve

*F*

^{max}, we need to know prior information about the initial state, meaning that the decoherence suppression scheme becomes state dependent. Thus, here, we focus on comparing

*F*

^{exp}with

*F*

^{fix}.

The numerical results for the state fidelities for reversing strengths
${p}_{r}^{\text{fix}}$ and
${p}_{r}^{\text{exp}}$ when *D* = 0.617 are shown in Fig. 5(a). Note that *F*^{exp} > *F*^{fix} when |*α*| is larger than |*β*|. Since our decoherence suppression scheme exploits weak measurement, the success probability of the scheme is not unity. Hence, the success probability is also an important parameter for quantifying the performance of the scheme. The success probabilities for
${p}_{r}^{\text{fix}}$ and
${p}_{r}^{\text{exp}}$, respectively, are given by

*P*of Eq. (3). Note that, in most cases, ${P}_{S}^{\text{max}}$ is lower than ${P}_{S}^{\text{fix}}$ and ${P}_{S}^{\text{exp}}$ since ${p}_{r}^{\text{max}}$ is chosen for maximizing the state fidelity

_{S}*F*.

Figure 5(b) represents the success probability dependencies on |*α*| and *p* for different reversing measurement strengths when *D* = 0.617. As shown in Fig. 5(b),
${P}_{S}^{\text{exp}}>{P}_{S}^{\text{fix}}$ for all values of |*α*| and *p*. In the single qubit case, the reversing measurement strength
${p}_{r}^{\text{exp}}=p+\left(1-p\right)D$ is more efficient than
${p}_{r}^{\text{max}}$ and
${p}_{r}^{\text{fix}}$ in terms of the success probability.

## A2. Two-qubit case: Both subsystems suffer from decoherence and two pairs of weak and reversing measurements are performed

We consider the situation shown in Fig. 1(b) in which the initial two-qubit entangled state |Φ〉 = *α*|00〉 + *β*|11〉, where |*α*|^{2} + |*β*|^{2} = 1, suffers from separate decoherence and two pairs of weak and reversing measurements are applied to suppress decoherence [24]. To simplify the situation, we assume that each subsystem undergoes the same magnitude of decoherence (*D _{A}* =

*D*=

_{B}*D*) and the strengths of weak measurements

*W*(

_{A}*p*) and

*W*(

_{B}*p*), and reversing measurements

*R*(

_{A}*p*) and

_{r}*R*(

_{B}*p*) performed on each subsystem are the same. Then, the output state

_{r}*ρ*

_{out}is given as

*P*=

_{S}*p*|

_{r}D̄*α*|

^{2}(

*Dp*+

_{r}*p*− 2) + (

_{r}*Dp*− 1)

_{r}^{2}(1 −

*p*

^{2}|

*β*|

^{2}+ 2

*p*|

*β*|

^{2}is the success probability. The state fidelity between the initial state and the output state is obtained to be

*F*is

*Dp̄*|

*β*|

^{2}< |

*α*|

^{2}<

*p̄*|

*β*|

^{2}. Otherwise,

*p*= 1 maximizes

_{r}*F*, meaning that the reversing measurement

*p*should be projection measurement regardless of the weak measurement strength

_{r}*p*.

As we did in the single qubit case, ${p}_{r}^{\text{fix}}$ is obtained by substituting $\alpha =1/\sqrt{2}$ into Eq. (12) and we obtain

*F*

^{fix}for ${p}_{r}^{\text{fix}}$ is given as

*F*

^{exp}for ${p}_{r}^{\text{exp}}=p+(1-p)D$ is calculated to be

The numerical results for the state fidelities *F* for
${p}_{r}^{\text{fix}}$ and
${p}_{r}^{\text{exp}}$ are shown in Fig. 6(a). As shown in Fig. 6(a), the general tendency of *F*^{fix} and *F*^{exp} are similar to the results of the single qubit case, see Fig. 5(a). *F*^{exp} is generally larger than *F*^{fix} when |*α*| is larger than |*β*|.

Finally, the success probabilities for ${p}_{r}^{\text{fix}}$ and ${p}_{r}^{\text{exp}}$, respectively, are calculated to be

Figure 6(b) shows the success probabilities *P _{S}* for various reversing measurement strength

*p*. As shown in Fig. 6(b), ${P}_{S}^{\text{exp}}$ is always larger than ${P}_{S}^{\text{fix}}$ in any combination of |

_{r}*α*| and

*p*. The general tendency of the success probabilities are similar to the single qubit case in that ${P}_{S}^{\text{exp}}$ is larger than ${P}_{S}^{\text{fix}}$.

## A3. Two-qubit case: Both subsystems suffer from decoherence and one pair of weak and reversing measurements are performed

In this section, we consider the scenario of this paper, see Fig. 1(c). Each subsystem of the initial entangled state |Φ〉 = *α*|00〉 + *β*|11〉, where |*α*|^{2} + |*β*|^{2} = 1, undergoes separate decoherence and a set of weak measurement *W _{A}*(

*p*) and reversing measurement

*R*(

_{A}*p*) is performed only on the subsystem undergoing decoherence (A). If we assume each subsystem undergoes the identical decoherence (

_{r}*D*=

_{A}*D*=

_{B}*D*), the output state

*ρ*

_{out}is given as

*P*= |

_{S}*α*|

^{2}[

*p*−

*p*(

_{r}*D̄*+

*Dp*)] +

*p̄*(1 −

*Dp*) and the corresponding state fidelity between the initial state and the final state is calculated to be

_{r}*F*is rather complicated and cannot be simplified, we provide ${p}_{r}^{\text{fix}}$ instead of ${p}_{r}^{\text{max}}$. ${p}_{r}^{\text{fix}}$ is calculated to be

Since the final expressions of *F*^{fix} and
${P}_{S}^{\text{fix}}$ are also complicated, we omit their analytic expressions. *F*^{exp} and
${P}_{S}^{\text{exp}}$ values for
${p}_{r}^{\text{exp}}$, respectively, are given as

*F*

^{fix}and ${P}_{S}^{\text{fix}}$ due to their complexity, we show numerical results to compare

*F*

^{fix}and ${P}_{S}^{\text{fix}}$ with

*F*

^{exp}and ${P}_{S}^{\text{exp}}$, respectively. Figure 7(a) shows the state fidelity results for various reversing strengths. Since a single pair of weak and reversing measurements cannot suppress two independent decoherence, the state fidelities

*F*cannot achieve unity even in the case that

*p*→ 1. Note that

*F*→ 1 as

*p*→ 1 in both of Fig. 5(a) and Fig. 6(b). Another thing to note is that

*F*

^{fix}is larger than

*F*

^{exp}when |

*α*| is larger than |

*β*| in Fig. 7(a) while

*F*

^{exp}is larger than

*F*

^{fix}when |

*α*| is larger than |

*β*| in both of Fig. 5(a) and Fig. 6(a). Interestingly, the difference between

*F*

^{fix}, and

*F*

^{exp}is very small in any combination of |

*α*| and

*p*in Fig. 7(a).

The general tendency of the success probabilities in this case are opposite to the previous cases, see Fig. 7(b). ${P}_{S}^{\text{fix}}$ is always larger than ${P}_{S}^{\text{exp}}$ in Fig. 7(b); however, ${P}_{S}^{\text{exp}}$ is always larger than ${P}_{S}^{\text{fix}}$ in both of Fig. 5(b) and Fig. 6(b).

## A4. Two-qubit case: One subsystem suffers from decoherence and one pair of weak and reversing measurements are performed

Finally, we consider the case of Fig. 1(c) with *D _{A}* =

*D*and

*D*= 0. Here only the subsystem A of the initial entangled state |Φ〉 =

_{B}*α*|00〉 +

*β*|11〉, where |

*α*|

^{2}+ |

*β*|

^{2}= 1, suffers from decoherence and a set of weak measurement

*W*(

_{A}*p*) and reversing measurement

*R*(

_{A}*p*) is performed on the subsystem A. Then, the output state

_{r}*ρ*

_{out}becomes

*P*= |

_{S}*β*|

^{2}

*D̄p̄*+ |

*β*|

^{2}

*Dp̄p̄*+ |

_{r}*α*|

^{2}

*p̄*and the state fidelity between the input state and the output state is given as

_{r}*p*

^{max}that maximizes

*F*is

Then, ${p}_{r}^{\text{fix}}$ is evaluated by substituting $\alpha =1/\sqrt{2}$ into Eq. (25) and ${p}_{r}^{\text{fix}}$ is given as

The numerical results for the state fidelities and the success probabilities for various reversing measurement strengths are shown in Fig. 8. In this scheme, the general tendencies of the state fidelities and the success probabilities are similar to the single qubit case shown in Fig. 5, i.e., *F*^{exp} > *F*^{fix} when |*α*| is larger than |*β*| and
${P}_{S}^{\text{exp}}>{P}_{S}^{\text{fix}}$ regardless of |*α*| and *p*.

## A5. Conclusion

In conclusion, we have investigated the state fidelities *F* and the success probabilities *P _{S}* for various decoherence suppression schemes. Our results suggest that there is no reversing measurement which maximizes the state fidelity and the success probability simultaneously. In many cases, a trade-off relation between

*F*and

*P*holds, in other words, the higher the state fidelity, the lower the success probability, vice versa. Therefore, one should choose a proper

_{S}*p*value for a specific application, after carefully considering the trade-off relation.

_{r}## Acknowledgments

This work was supported in part by the National Research Foundation of Korea (Grant No. 2013R1A2A1A01006029 and 2011-0021452). H.-T.L. and J.-C.L. acknowledge support from the National Junior Research Fellowship (Grant No. 2012-000642 and 2012-000741, respectively).

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