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Quantum efficiency enhancement in selectively transparent silicon thin film solar cells by distributed Bragg reflectors

M. Y. Kuo, J. Y. Hsing, T. T. Chiu, C. N. Li, W. T. Kuo, T. S. Lay, and M. H. Shih

Open Access Open Access

Abstract

This work demonstrated a-Si:H thin-film solar cells with backside TiO2 / SiO2 distributed Bragg reflectors (DBRs) for applications involving building-integrated photovoltaics (BIPVs). Selectively transparent solar cells are formed by adjusting the positions of the DBR stop bands to allow the transmission of certain parts of light through the solar cells. Measurement and simulation results indicate that the transmission of blue light (430 ~500 nm) with the combination of three DBR mirrors has the highest increase in conversion efficiency.

©2012 Optical Society of America

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Figures (4)
Fig. 1
Fig. 1 Illustrations of DBRs are on the back side of n-type ZnO transparent contact, and their calculated reflective spectra. (a) DBR1, (b) DBR2, and (c) Wavelength selectivity transparent DBR is combined with DBR1 and DBR2.

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Fig. 2
Fig. 2 (a) Schematic diagram of the DBR structure based on TiO2/SiO2. (b) Reflectance of this DBR structure. The measurement result depicted as red line contains DBR structure and reference cell. The simulation result depicted as blue line only contains DBR structure. (c) Blue color observed from the solar cell with DBRs under the strong white light source. This indicates only incident light around 450 nm wavelength can transmit through the DBRs.

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Fig. 3
Fig. 3 (a) J-V curves for semi-transparent BIPV with or without DBR. (b) Measured EQE spectrum for semi-transparent BIPV with and without back contacted DBR.

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Fig. 4
Fig. 4 (a) The refractive indices as functions of wavelength for a-Si, TiO2, SiO2, ZnO. (b) Extinction coefficients for a-Si and TiO2. (c) Simulated EQE spectrum for semi-transparent BIPV without DBR (blue curve) and with DBR (red curve).

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Tables (1)

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Table 1 Simulation Parameters for Field Dependent Mobility Model for a-Si (m.k.s. Units)

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Equations (1)

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μ= μ 0 ⋅ ( 1 1+ ( μ 0 ⋅E v sat ) β ) 1 β μ 0 = μ max − μ min 1+ ( N N ref ) α + μ min
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