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Energy transfer from InGaN quantum wells to Au nanoclusters via optical waveguiding

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Abstract

We present the first observation of resonance energy transfer from InGaN quantum wells to Au nanoclusters via optical waveguiding. Steady-state and time-resolved photoluminescence measurements provide conclusive evidence of resonance energy transfer and obtain an optimum transfer efficiency of ~72%. A set of rate equations is successfully used to model the kinetics of resonance energy transfer.

©2011 Optical Society of America

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Figures (5)

Fig. 1
Fig. 1 Schematic representation of the resonance energy transfer from the InGaN quantum well to Au NCs via optical waveguiding.
Fig. 2
Fig. 2 (a) PL spectrum of Au NCs (b) PL excitation spectrum of Au NCs (c) PL spectrum of the InGaN quantum well.
Fig. 3
Fig. 3 PL spectra of the InGaN quantum well in the presence (the solid line) and absence (the dashed line) of Au NCs. The inset displays the photograph of the investigated sample under laser excitation (the spot marked by an arrow), showing the red emission of Au NCs (the region marked by the open ellipse).
Fig. 4
Fig. 4 (a) PL decay profile of the InGaN quantum well in the absence (open circles) and present (open squares) of Au NCs. The dashed line (solid line) is the fitted curve using Eq. (1) (Eq. (5)). (b) PL decay profile of Au NCs in the absence (open circles) and present (open squares) of InGaN quantum wells. The dashed line (solid line) is the fitted curve using Eq. (2) (Eq. (6)).
Fig. 5
Fig. 5 The dependence of the PL intensity in InGaN quantum wells on excitation density. The nearly linear dependence reveals that recombination is dominated by excitons.

Tables (1)

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Table 1 The parameters used in the fits according to Eqs. (5) and (6)

Equations (9)

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n D ( t ) = n D ( 0 ) e ( k D t ) β 1 ,
n A ( t ) = n A ( 0 ) e ( k A t ) β 2 ,
d n D A ( t ) d t = k D n D A ( t ) k E T n D A ( t ) ,
d n A D ( t ) d t = k N C n A D ( t ) + k E T n A D ( t ) ,
n D A ( t ) = n D A ( 0 ) e ( k D t ) β 1 × e ( k E T t ) 1 / 2 ,
n A D ( t ) = A e ( k A t ) β 2 B e ( k D t ) β 1 × e ( k E T t ) 1 / 2 ,
E = 1 I D A I D ,
< τ > = 1 k β Γ ( 1 β ) ,
E = k E T k E T + k D .
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