Abstract

We report a new kind of comb filters based on fiber Bragg gratings in graded-index multimode fibers. It produces two groups of spectra with a total of 36 reflection peaks that correspond to 18 principal modes and cross coupled modes. The mode indices and wavelength spacings have been investigated theoretically and experimentally. This kind of comb filters may be used to construct multi-wavelength light sources for sensing, optical communications, and instrumentations.

© 2005 Optical Society of America

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References

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Appl. Opt. (1)

IEEE, J. Quantum Electron. (1)

K. Kitayama, S. Seikkai, and N. Uchida, �??Impulse Response prediction based on experimental mode coupling coefficiednt in a 10-km long graded-index fiber,�?? IEEE, J. Quantum Electron. QE-6, 356-362, (1980).
[CrossRef]

J. Lightwave Technol. (1)

Opt. Commun. (2)

Y. Sun, T. Szkopek, P. W. E. Smith, �??Demonstration of narrowband high-reflectivity Bragg gratings in a novel multimode fiber,�?? Opt. Commun. 223, 91-95, (2003).
[CrossRef]

Xiufeng Yang, Chunliu Zhao, Junqiang Zhou, Xin Guo, Junhong Ng, Xiaoqun Zhou, Chao Lu, �??The characteristics of fiber slanted gratings in multimode fiber,�?? Opt. Commun. 229, 161�??165, (2004).
[CrossRef]

Smart Mater. Struct. (1)

W. Zhao and Richard O Cllaus, �??Optical fiber grating sensors in multimode fibers,�?? Smart Mater. Struct. 9, 212-214, (2000).
[CrossRef]

Other (1)

M. J. Adams, An Introduction to Optical Waveguides (John Wiley & Sons, 1980), p. 302.

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Figures (4)

Fig. 1.
Fig. 1.

Experimental measurement of multimode fiber gratings

Fig. 2.
Fig. 2.

The transmission and reflection of a 20 mm long multimode fiber grating

Fig. 3.
Fig. 3.

The reflection spectrum of a 20 mm long MFBG. Two groups of reflections correspond to 18 principal modes (strong) and neighbouring cross coupled modes (weak).

Fig. 4
Fig. 4

The transmission of a 20 mm long MFBGs shows the principal modes coupling.

Equations (8)

Equations on this page are rendered with MathJax. Learn more.

n ( r ) = { n 0 1 2 Δ ( r a ) 2 ( 0 < r < a ) n 0 1 2 Δ = n a ( r a )
V = 2 π a N A λ
N A = n 0 2 Δ
M = V 2
n m = n 0 1 4 Δ m V
n m = n 0 m λ 0 N A 2 π a n 0
{ λ m = 2 n m Λ λ m cross = ( n m + n m + 1 ) Λ
Δλ = λ 0 2 N A 2 π a n 0 2

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