Abstract

Spectra of the 4.5-μ N2O band were obtained after a beam of continuous radiation passed through two cells containing mixtures of N2O and N2. The total pressure and absorber concentration of one cell were such that its absorption lay essentially in the region where the band absorptance is approximately proportional to the square root of the total pressure and absorber concentration. The total pressure and N2O concentration in the second cell were varied over a wide range and two empirical expressions were found relating the total absorptance of the 4.5-μ N2O band to the pressures and absorber concentrations of the two cells.

© 1963 Optical Society of America

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References

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  1. D. A. Gryvnak and J. H. Shaw, J. Opt. Soc. Am. 52, 539 (1962).
    [CrossRef]
  2. D. E. Burch and D. Williams, Appl. Opt. 1, 587 (1962).
    [CrossRef]
  3. D. E. Burch and D. Williams, Appl. Opt. 1, 473 (1962).
    [CrossRef]
  4. J. H. Shaw, “Empirical Methods for Computing the Integrated Absorptances of Infrared Bands of Atmospheric Gases at Nonuniform Pressures,” Appl. Opt. (to be published).

1962 (3)

Appl. Opt. (2)

J. Opt. Soc. Am. (1)

Other (1)

J. H. Shaw, “Empirical Methods for Computing the Integrated Absorptances of Infrared Bands of Atmospheric Gases at Nonuniform Pressures,” Appl. Opt. (to be published).

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Figures (3)

Fig. 1
Fig. 1

Typical spectra for the case when Cell 2 contained Sample 2 and the conditions in Cell 1 were varied.

Fig. 2
Fig. 2

The ln of the total absorptance vs the ln of the sum [ w 1 ( P e 1 ) 0.7 + w 2 ( P e 2 ) 0.7 ] for Samples 1, 2, 3, and 4.

Fig. 3
Fig. 3

The total absorptance vs the ln of the sum [ w 1 ( P e 1 ) 0.7 + w 2 ( P e 2 ) 0.7 ] for Samples 1, 2, 3, and 4.

Tables (1)

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Table I Description of conditions in Cell 2.

Equations (9)

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P e = P + ( B 1 ) p ,
A = C [ w ( P e ) a ] b ,
A = D log ( w P e a ) + E ,
A = C [ w 1 ( P e 1 ) a + w 2 ( P e 2 ) a ] b ,
A = 18.0 [ w ( P e ) 0.7 ] 0.53
A = 40 log ( w P e 0.7 ) + 15 ,
[ w 1 ( P e 1 ) 0.7 + w 2 ( P e 2 ) 0.7 ]
A = 18.2 [ w 1 ( P e 1 ) 0.7 + w 2 ( P e 2 ) 0.7 ] 0.54 ,
A = 48 log [ w 1 ( P e 1 ) 0.7 + w 2 ( P e 2 ) 0.7 ] + 9 ,