Abstract

A method is described for analyzing the light remitted from certain Daylight Fluorescent Colors into its reflected and fluoresced components.

The evaluation in both cases is on any energy basis (expressed on a percentage scale) as a function of the wavelength of the exciting radiation when the energy content of the exciting beam is held constant.

© 1951 Optical Society of America

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References

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  1. J. Opt. Soc. Am. 25, 305 (1935).

1935 (1)

J. Opt. Soc. Am. (1)

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Figures (10)

Fig. 1
Fig. 1

Spectrophotometric curves obtained for a rhodamine formulation exhibiting “daylight fluorescence.” The upper curve is without the filter, the lower curve with the filter. The dashed portion covers the region of inadequate instrument sensitivity.

Fig. 2
Fig. 2

Transmittance curve of the blue-green filter used in this experiment.

Fig. 3
Fig. 3

The sensitivity characteristic of the PJ 15 phototube in our equipment.

Fig. 4
Fig. 4

The computed reflectance of the fluorescing material.

Fig. 5
Fig. 5

The computed fluorescence at 628 mμ of the fluorescing material for incident wavelengths from 400 to 700 mμ.

Fig. 6
Fig. 6

Schematic diagram of the apparatus used to obtain a synthetic fluorescing material. The reflected component is derived from the sample beam of the spectrophotometer passing through the usual optics and through the front of the sphere to the sample. The synthetic fluoresced component is introduced through the back of the sample.

Fig. 7
Fig. 7

The transmittance of the interference filter (obtained with a slit width of about 0.3 mμ). This curve illustrates the energy distribution of the synthetic fluoresced component.

Fig. 8
Fig. 8

Spectrophotometric curves obtained with and without the blue-green filter for the synthetic fluorescing material.

Fig. 9
Fig. 9

Computed (circles) and measured (solid line) values of the reflectance of the synthetic fluorescing material.

Fig. 10
Fig. 10

Perspective representation of the type of fluorescing material discussed. λ is the wavelength of the incident beam, λ′ is the wavelength of the light sent back. The reflectance curve, drawn on the diagonal, is shown having finite thickness for the sake of clarity, actually in this representation it should be a portion of a plane.

Equations (13)

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M [ a E 1 ( λ ) + b E 2 ( λ ) ] = a M [ E 1 ( λ ) ] + b M [ E 2 ( λ ) ] .
M [ E ( λ ) ] = 0 F ( λ , λ ) E ( λ ) d λ .
I 0 ( λ ) cos 2 θ R ( λ ) S ( λ ) = I 0 ( λ ) sin 2 θ R MgO ( λ ) S ( λ ) .
R ( λ ) / R MgO ( λ ) = tan 2 θ .
I 0 ( λ ) cos 2 θ R ( λ ) S ( λ ) + I 0 ( λ ) cos 2 θ R f ( λ ) S ( λ f ) = I 0 ( λ ) sin 2 θ R MgO ( λ ) S ( λ )
r 1 = tan 2 θ = R ( λ ) R MgO ( λ ) + R f ( λ ) S ( λ f ) R MgO ( λ ) S ( λ ) .
I 0 ( λ ) cos 2 θ R ( λ ) S ( λ ) F ( λ ) + I 0 ( λ ) cos 2 θ R f ( λ ) S ( λ f ) F ( λ f ) = I 0 ( λ ) R MgO ( λ ) sin 2 θ S ( λ ) F ( λ ) ,
r 2 = tan 2 θ = R ( λ ) R MgO ( λ ) + R f ( λ ) S ( λ f ) F ( λ f ) R MgO ( λ ) S ( λ ) F ( λ ) .
R f ( λ ) R MgO ( λ ) [ S ( λ f ) S ( λ ) ( 1 - F ( λ f ) F ( λ ) ) ]
S ( λ f ) S ( λ ) ( 1 - F ( λ f ) F ( λ ) )
R f ( λ ) R MgO ( λ ) = r 1 - r 2 S ( λ f ) / S ( λ ) [ 1 - ( F ( λ f ) / F ( λ ) ) ] .
R ( λ ) R MgO ( λ ) = r 2 F ( λ ) - r 1 F ( λ f ) F ( λ ) - F ( λ f ) .
I 0 ( λ ) T / I 0 ( λ ) R MgO .