Abstract
A simple method has been developed for the determination of <sup>6</sup>Li atom % using combined atomic emission–absorption spectrometry employing a commonly available natural lithium hollow cathode lamp. Unlike in previous practice, there is no need for specially fabricated and high cost <sup>6</sup>Li and <sup>7</sup>Li monoisotopic lamps in this method. The method requires adjustment of total lithium contents of the sample, i.e., <sup>6</sup>Li + <sup>7</sup>Li, to 2 μg·mL<sup>−1</sup> based upon atomic emission spectroscopy (AES) (<i>C</i><sub>aes</sub>) against a 2 μg·mL<sup>−1</sup> natural lithium standard. The concentration of the sample was then analyzed by atomic absorption spectroscopy (AAS) measurements (<i>C</i><sub>aas</sub>). The difference between the concentration measured by AES and AAS, i.e., <i>C</i><sub>aes</sub> − <i>C</i><sub>aas</sub>, was calculated. The magnitude of the difference was found to be a function of <sup>6</sup>Li fraction in the sample. A calibration curve was constructed by plotting <sup>6</sup>Li atom % versus [(<i>C</i><sub>aes</sub> − <i>C</i><sub>aas</sub>)/<i>C</i><sub>aes</sub>] × 100. <sup>6</sup>Li atom % of an unknown sample can be evaluated by putting its [(<i>C</i><sub>aes</sub> − <i>C</i><sub>aas</sub>)/<i>C</i><sub>aes</sub>] × 100 value in the calibration curve. The method is fast, convenient, and precise.
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