Abstract

The bulk and surface absorption coefficients of CdTe modulator crystals at 10.6 μm were compared with those of single-crystal KCl and NaCl which served to calibrate the laser calorimeter. High-resistivity (>107 ohm/cm) CdTe crystals exhibited a bulk absorption coefficient of 0.0014 cm−1.

© 1982 Optical Society of America

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References

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  1. H. B. Rosenstock, M. Hass, D. A. Gregory, J. A. Harrington, Appl. Opt. 16, 2837 (1977).
    [CrossRef] [PubMed]
  2. M. Hass, J. W. Davisson, P. H. Klein, L. L. Boyer, J. Appl. Phys. 45, 3959 (1974).
    [CrossRef]
  3. D. A. Pinnow, T. C. Rich, Appl. Opt. 12, 984 (1973).
    [CrossRef] [PubMed]
  4. E. Bernal G., Appl. Opt. 14, 314 (1975).
    [CrossRef] [PubMed]

1977

1975

1974

M. Hass, J. W. Davisson, P. H. Klein, L. L. Boyer, J. Appl. Phys. 45, 3959 (1974).
[CrossRef]

1973

Bernal G., E.

Boyer, L. L.

M. Hass, J. W. Davisson, P. H. Klein, L. L. Boyer, J. Appl. Phys. 45, 3959 (1974).
[CrossRef]

Davisson, J. W.

M. Hass, J. W. Davisson, P. H. Klein, L. L. Boyer, J. Appl. Phys. 45, 3959 (1974).
[CrossRef]

Gregory, D. A.

Harrington, J. A.

Hass, M.

H. B. Rosenstock, M. Hass, D. A. Gregory, J. A. Harrington, Appl. Opt. 16, 2837 (1977).
[CrossRef] [PubMed]

M. Hass, J. W. Davisson, P. H. Klein, L. L. Boyer, J. Appl. Phys. 45, 3959 (1974).
[CrossRef]

Klein, P. H.

M. Hass, J. W. Davisson, P. H. Klein, L. L. Boyer, J. Appl. Phys. 45, 3959 (1974).
[CrossRef]

Pinnow, D. A.

Rich, T. C.

Rosenstock, H. B.

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Figures (5)

Fig. 1
Fig. 1

Experimental arrangement for calorimetric measurement of absorption coefficient at 10.6 μm in CdTe crystals.

Fig. 2
Fig. 2

Thermal response for 1-cm × 1-cm × 10-cm crystal of KCl.

Fig. 3
Fig. 3

Thermal response for 1-cm × 1-cm × 10-cm crystal of NaCl (NaCl-1).

Fig. 4
Fig. 4

Thermal response for 1-cm × 1-cm × 3-cm crystal of NaCl (NaCl-2).

Fig. 5
Fig. 5

Thermal response for 1-cm × 1-cm × 3-cm crystal of CdTe.

Tables (1)

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Table I Bulk Absorption Coefficient β (cm−1) and Surface Absorption S

Equations (5)

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T - T s = P T A L C v ( n 2 + 1 2 n ) { β L t             t ( ½ L ) 2 C v 6 k , β L t + 2 S [ t - ( ½ L ) 2 C v 6 k ]             t ( ½ L ) 2 C v 6 k ,
β = A C v P T ( 2 n n 2 + 1 ) ( d T d t | T 1 heating + | d T d t | T 1 cooling ) .
β L + 2 S = A L C v P T ( 2 n n 2 + 1 ) ( d T d t | T 2 heating + | d T d t | T 2 cooling ) ,
2 S = - 24 b k A P T L ( 2 n 1 + n 2 ) .
β L + 2 S = A L C v P T ( 2 n 1 + n 2 ) T eq τ .

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