Abstract

Optical systems for correcting the axial chromatic aberration of the eye are studied theoretically. Compact(cemented) doublets or triplets for this cannot avoid introducing unwanted transverse color. A new air-spaced system is described which avoids this problem. Experimental results confirmed that this lens performed well over a 14-deg field of view.

© 1981 Optical Society of America

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References

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  1. G. Wald, D. R. Griffin, J. Opt. Soc. Am. 37, 321 (1947).
    [CrossRef] [PubMed]
  2. R E. Bedford, G. Wyszecki, J. Opt. Soc. Am. 47, 564 (1957).
    [CrossRef] [PubMed]
  3. H. H. Hopkins, Wave Theory of Aberrations (Clarendon, Oxford, 1950).

1957 (1)

1947 (1)

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Figures (9)

Fig. 1
Fig. 1

Zero power triplet for correcting the axial chromatic aberration of the human eye.

Fig. 2
Fig. 2

Axial chromatic aberration of (a) uncorrected and (b) corrected eye of a single observer. (Ordinates are expressed in diopters necessary to correct the eye at each wavelength. Reference wavelength is 578 nm.)

Fig. 3
Fig. 3

Chromatic angular spread associated with triplet for a field size of 1.0 deg.

Fig. 4
Fig. 4

Zero power doublet for correcting the axial chromatic aberration of the human eye.

Fig. 5
Fig. 5

Paraxial ray trace through an air-spaced optical system.

Fig. 6
Fig. 6

Air-spaced optical system for correcting the axial chromatic aberration of the human eye.

Fig. 7
Fig. 7

Comparison of the corrected axial chromatic aberration for (a) original triplet and (b) air-spaced lens.

Fig. 8
Fig. 8

Comparison of the chromatic angular spread for both the old and new corrector.

Fig. 9
Fig. 9

Measurements taken by two observers with and without the new chromatic corrector.

Equations (13)

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C L = ½ i h i 2 K i μ i μ i - 1 ,
C T = i h i h ¯ i K i μ i μ i - 1 ,
C L = ½ h 1 2 i K i μ i μ i - 1 ,
C T = 2 h ¯ 1 h 1 C L .
C ˜ L = i K i μ i μ i - 1 ,
C ˜ T = h ¯ 1 C ˜ L .
i = 1 2 K i = 0 ,
C ˜ L = K 1 V 2 - V 1 V 1 V 2 = - 1.0
K 1 = V 1 V 2 V 1 - V 2 .
Δ c = 1 / ( μ 2 - μ 1 ) ,
C ˜ L = C ˜ 1 L + C ˜ 2 L = - 1.0 ,
C ˜ T = h ¯ 1 C ˜ 1 L + h ¯ 2 C ˜ 2 L = 0.0 ,
C ˜ 1 L = h ¯ 2 / ( h ¯ 2 - h ¯ 1 ) , or C ˜ 1 L = - d 1 / d 2 - 1 ,

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