Abstract

The refractive index of optical materials can be modified by means of neutron irradiation. By varying the radiation dose over selected areas of a lens according to some given law, the local change in the refractive index can be adjusted to correct for different types of optical aberrations. The particular case of spherical aberration is treated in detail. It is shown that irradiation leads to index modifications of the required order of magnitude and that irradiation times are acceptable. Moreover, the stability of the index modifications, the possibility of bleaching—without curing the index—and the absence of residual radioactivity make an irradiated lens suitable for optical applications. The optician has thus at his disposal a new parameter.

© 1971 Optical Society of America

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References

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  1. This article is an abstract of a thesis entitled “Some Applications of Corpuscular and Electromagnetic Radiation to Optics” (thesis worked on at the Commissariat à l’Energie Atomique).
  2. A. Paymal, Opt. Acta 9, 149 (1962).
    [CrossRef]
  3. W. Primak, Phys. Rev. 110, 1240 (1958).
    [CrossRef]
  4. Prasada Rao, Rev. d’Opt. 45, 393 (1966).

1966 (1)

Prasada Rao, Rev. d’Opt. 45, 393 (1966).

1962 (1)

A. Paymal, Opt. Acta 9, 149 (1962).
[CrossRef]

1958 (1)

W. Primak, Phys. Rev. 110, 1240 (1958).
[CrossRef]

Paymal, A.

A. Paymal, Opt. Acta 9, 149 (1962).
[CrossRef]

Primak, W.

W. Primak, Phys. Rev. 110, 1240 (1958).
[CrossRef]

Rao, Prasada

Prasada Rao, Rev. d’Opt. 45, 393 (1966).

Opt. Acta (1)

A. Paymal, Opt. Acta 9, 149 (1962).
[CrossRef]

Phys. Rev. (1)

W. Primak, Phys. Rev. 110, 1240 (1958).
[CrossRef]

Rev. d’Opt. (1)

Prasada Rao, Rev. d’Opt. 45, 393 (1966).

Other (1)

This article is an abstract of a thesis entitled “Some Applications of Corpuscular and Electromagnetic Radiation to Optics” (thesis worked on at the Commissariat à l’Energie Atomique).

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Figures (17)

Fig. 1
Fig. 1

Variation in the index of a boron silicate B40, Pyrex glass type, as a function of the neutron dose.

Fig. 2
Fig. 2

Irradiated disk showing two indexes of refraction.

Fig. 3
Fig. 3

Autoradiography of the disk shown in Fig. 2: (a) cadmium protected zone; (b) cadmium nonprotected zone.

Fig. 4
Fig. 4

Glasses transmission before and after bleaching: (1) not irradiated; (2) and (3) disks bleached (uv + 125°C) for 4 days; (2) protected part of the disk; (3) exposed part of the disk; (4) glass bleached for 4 days (uv + 80°C); (5) unbleached glass (1 year after irradiation).

Fig. 5
Fig. 5

Principle of the irradiation device.

Fig. 6
Fig. 6

Experimental set up for irradiation: (a) cadmium collimator; (b) aluminum spacer; (c) disk or lens to be corrected; (d) gold or copper foil; (e) aluminum foil used as Co and Ni envelope; (f) main attenuator; (g) Ni detector, Co detector; (h) complementary attenuator; (i) aluminum casing; (j) neutron flux.

Fig. 7
Fig. 7

Neutron collimator.

Fig. 8
Fig. 8

(a) Computed attenuator. (b) Equivalent attenuators. (c) Main attenuator. (d) Complementary attenuator.

Fig. 9
Fig. 9

Autoradiography of a lens irradiated according to −h2 law.

Fig. 10
Fig. 10

Autoradiography of a lens irradiated according to +h4 law.

Fig. 11
Fig. 11

Fringe observations: (a) nonirradiated control lens: 3 to 4 fringes; (b) lens irradiated up to 1.6 × 1017n/cm2: 3 fringes; (c) lens irradiated up to 7 × 1017n/cm2: 1 fringe.

Fig. 12
Fig. 12

Nonirradiated lens (f/5 aperture).

Fig. 13
Fig. 13

Corrected lens (slight eccentricity of the reference sphere), 1 to 2 fringes.

Fig. 14
Fig. 14

Schematic of the device for irradiation in a Cd box (a) cadmium; (b) lens; (c) neutron flux.

Fig. 15
Fig. 15

Lens corrected by discontinuous irradiation in a Cd box (2 indexes).

Fig. 16
Fig. 16

Identical to Fig. 15 but important eccentricity of the standard sphere and setting defect.

Fig. 17
Fig. 17

Identical to Fig. 15 but slight eccentricity of the standard sphere and setting defect.

Tables (1)

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Table I Values of y

Equations (6)

Equations on this page are rendered with MathJax. Learn more.

Δ n = - K ( n - 1 ) h 2
Δ n = K h 4 / ( 4 e f 3 )
e = e 0 - R + ( R 2 - h 2 ) 1 2
Δ n = - 0.61 × 10 - 3 h 2
Δ n = 2.28 × 10 - 3 h 2 .
y = 1 / ψ log e f ( h ) / [ g ( h ) ] ,

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