Abstract

Among many possible applications of the extremely high brightness temperature and the radiation density obtainable with the optical maser, a high energy electron accelerator is proposed and discussed in this paper. It consists of a cylindrical tube of maser material excited by a pumping radiation through an interference filter coated on its outer surface and, it generates an oscillation in a TM0NM type mode. An optical peak power of 10 kw/cm2 was calculated to accelerate electrons by 109 ev/meter. A gas-filled cavity is proposed for velocity matching. Selection of the particular mode might be made by placing a periodically printed absorption layer on the inner surface of the maser cylinder. However, mode separation would be extremely difficult because of thermal expansion of the maser material.

© 1962 Optical Society of America

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References

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  1. K. Shimoda, H. Takahasi, C. H. Townes, J. Phys. Soc. Japan 12, 686 (1957).
    [CrossRef]

1957 (1)

K. Shimoda, H. Takahasi, C. H. Townes, J. Phys. Soc. Japan 12, 686 (1957).
[CrossRef]

Shimoda, K.

K. Shimoda, H. Takahasi, C. H. Townes, J. Phys. Soc. Japan 12, 686 (1957).
[CrossRef]

Takahasi, H.

K. Shimoda, H. Takahasi, C. H. Townes, J. Phys. Soc. Japan 12, 686 (1957).
[CrossRef]

Townes, C. H.

K. Shimoda, H. Takahasi, C. H. Townes, J. Phys. Soc. Japan 12, 686 (1957).
[CrossRef]

J. Phys. Soc. Japan (1)

K. Shimoda, H. Takahasi, C. H. Townes, J. Phys. Soc. Japan 12, 686 (1957).
[CrossRef]

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Figures (2)

Fig. 1
Fig. 1

Schematic diagram of an electron linear accelerator by optical maser.

Fig. 2
Fig. 2

Dielectric tube in a gas-filled cavity for velocity-matching.

Equations (11)

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δ ν = 4 π k T n ( Δ ν ) 2 P ,
k T n = h ν 0 N * N * N = h ν 0 1 exp ( h ν 0 / k T e ) .
E z ( r · θ , z , t ) = E 0 T 0 ( k r r ) cos ( k z Z ) e j ω t .
J 0 ( k r r ) 2 π k r r cos ( k r r π 4 ) .
P = c ( 1 R ) E 2 8 π S , S = 2 π a l ,
E 0 2 = π k r a E 2 = 8 π 3 N c ( 1 R ) P S .
N = k r a π = 2 a λ r .
k 0 2 = ( 2 π λ 0 ) 2 = k r 2 + k z 2 ,
L 1 L 2 = ( n 1 ) c υ p υ e n .
π e 4 Z 2 N p 2 υ e 2 cot 2 θ 2 ,
1 β = ( n 1 ) 1 2 ( λ 0 λ r ) 2 .

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