## Abstract

Optical logic circuits using function/interconnection modules are needed for the construction of optical digital computers. Construction of function/interconnection modules by holographic techniques is proposed. Holographic function/interconnection modules do not require the complementary inputs that were needed for modules proposed previously. Moreover, a number of modules can be constructed in one filtering system by our holographic technique. Experiments describing this kind of implementation are described. Potential integration of the modules into one filtering system and the power efficiency of proposed modules are also discussed.

© 1991 Optical Society of America

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### Equations (3)

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(1)
$$\begin{array}{l}{F}_{LA}({\nu}_{x},{\nu}_{y})=3/8\times \{[(2/3)\text{exp}(j5\pi l{\nu}_{x})-(1/3)\text{exp}(j3\pi l{\nu}_{x})\\ +\hspace{0.17em}(2/3)\text{exp}(j\pi l{\nu}_{x})+(2/3)\text{exp}(-j\pi l{\nu}_{x})\\ -\hspace{0.17em}(1/3)\text{exp}(-j3\pi l{\nu}_{x})+(2/3)\text{exp}(-j5\pi l{\nu}_{x})]\text{exp}(-j3\pi l{\nu}_{y})\\ +\hspace{0.17em}[(-2/3)\text{exp}(j5\pi l{\nu}_{x})+(1/3)\text{exp}(j3\pi l{\nu}_{x})+(2/3)\text{exp}(j\pi l{\nu}_{x})\\ -\hspace{0.17em}(2/3)\text{exp}(-j\pi l{\nu}_{x})-(1/3)\text{exp}(-j3\pi l{\nu}_{x})+(2/3)\text{exp}(-j5\pi l{\nu}_{x})]\\ \times \hspace{0.17em}\text{exp}(-j\pi l{\nu}_{y})+[(2/3)\text{exp}(j5\pi l{\nu}_{x})+(1/3)\text{exp}(j3\pi l{\nu}_{x})\\ -\hspace{0.17em}(2/3)\text{exp}(j\pi l{\nu}_{x})+(2/3)\text{exp}(-j\pi l{\nu}_{x})+(1/3)\text{exp}(-j3\pi l{\nu}_{x})\\ -\hspace{0.17em}(2/3)\text{exp}(-j5\pi l{\nu}_{x})]\text{exp}(j\pi l{\nu}_{y})+[(-2/3)\text{exp}(j5\pi l{\nu}_{x})\\ +\hspace{0.17em}\text{exp}(j3\pi l{\nu}_{x})-(2/3)\text{exp}(j\pi l{\nu}_{x})-(2/3)\text{exp}(-j\pi l{\nu}_{x})\\ +\hspace{0.17em}\text{exp}(-j3\pi l{\nu}_{x})-(2/3)\text{exp}(-j5\pi l{\nu}_{x})]\text{exp}(j3\pi l{\nu}_{y})]\},\end{array}$$
(2)
$${F}_{CNT}({\nu}_{x},{\nu}_{y})=(1/4)[\text{exp}(j3\pi l{\nu}_{y})+\text{exp}(j\pi l{\nu}_{y})+\text{exp}(-j\pi l{\nu}_{y})+\text{exp}(-j3\pi l{\nu}_{y})],$$
(3)
$$\eta =(\sum \text{power}\hspace{0.17em}\text{of}\hspace{0.17em}\text{ON}\hspace{0.17em}\text{pixels})/(\sum \text{power}\hspace{0.17em}\text{all}\hspace{0.17em}\text{pixels}).$$